B2 D B' // EO (3)
L D  // RZP (2)
F2 D2 R U2 R L F2 L D  // DR (9/14)
(F2 D2 R' B2 U2 R)  // HTR (6/20)
(F2 L2 B2 D2 B2)   // Slice 2e2e (5/25)

solution:
B2 D B' L D F2 D2 R U2 R L F2 L D B2 D2 B2 L2 F2 R' U2 B2 L2 R' U2 B2 R2 L2 (28)

idk, tried to insert slice

(B F2 D' R' F)     // EO [5/5]
(L U' L2 D2 F2 D2 R2 D R')   // DR-2c3 [9/14]
(U)   // DR-4b2 [1/15]
L2 F2 D' L2 D    // HTR [5/20]
L2 U2 D2 B2 R L' B2 R' L  // finish [9/29]


First, i found L2 F2 U' F2 U L2 F2 R' L F2 R L' U2 D2 on this dr (4b2,2e), which leaves unsolved E-slice edges in 29-moves, but unfortunately I do not know how to efficiently proceed with slice insertions. Then, I started experimenting with the idea to eliminate that - to put it mildly - uncomfortable slice issue, and found L2 F2 D' L2 D L2 F2 R' L F2 R L, but this only made my situation worse. Accidentally I discovered that F2 D2 F2 U2 B2 U2, and even F2 U2 D2 B2 resolves that 2e2e and solves the cube, but i was disappointed about adding so many moves. Miraculously, hope appeared when i randomly inserted F2 U2 D2 B2 in the F2 D' L2 D L2 F2 * R' L F2 R L sequence. Because of that, I found that I could rewrite the rest of the moves, finishing with L2 F2 D' L2 D L2 F2 * R' L F2 R L'.
I am really excited about my result, and I am looking forward to my future progress in FMC.

Best regards

D F D' L' U' B R L'	// RZP [8/8]
(D' F2 U2 B2 U' D' F2 U' D2 R)	// DR 2c3 [10/18]
B2 D R2 B2 D2 F2 B2 U'	// DR 4a1 [8/26]
(U2 B2 F2 R2 F2 U2 R2 F2 L2 U2 D L2 U D')	// slice [14/40]
	
solution:	
D F D' L' U' B R L' B2 D R2 B2 D2 F2 B2 U2 D L2 D' U2 L2 F2 R2 U2 F2 R2 F2 B2 U2 R' D2 U F2 D U B2 U2 F2 D [40-1=39]