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Oberlin Challenge I 2025
2025-10-11 ~ 2025-10-11
Zach Baruch
Detected as competition participant
First
#5Mean28.00Single26 (29 / 26 / 29)
Attempt 1
Scramble
R' U' F U' R' D2 F' U2 L2 D R' F D2 R2 F2 R2 L F2 R D2 L U' R' U' F
Results
29
R' L2 F B L U F' U2 L2 F L2 F2 B' D B' L2 B2 R2 U2 R2 D2 B D2 R2 B L2 U2 F2 L2
L2 R' F B L U, F' U2 L2 F L2 B' F2 D // 14 2c3 4e B' (L2 F2 U2 L2 B' R2 D2 B') (D2 R2 U2 R2 B2 L2) // 29 finish
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March 26, 2026 8:03 AM
Attempt 2
Scramble
R' U' F D2 L' F2 L' U2 R D2 B' D B' D B2 L' F' U F2 R2 B2 R' U' F
Results
26
B R' F' U2 F' U2 D2 R2 F' B2 D2 R2 U2 L2 B2 U' F2 B' U2 D2 B' U' D2 R U F
B R' (F' U' R') (U, D2 B U2 D2 B F2 U) // 13 2c3 2e B' R2 F' R2 L2 D2 B // HTR with extension U2 L2 D2 R2 F2 // 25 slice, +1
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March 26, 2026 8:09 AM
Attempt 3
Scramble
R' U' F U B' R2 L U2 B' L' D B' U B' L2 D2 B R2 D2 F2 U2 R' U' F
Results
29
B L' U R F' U2 F2 L F2 L2 D2 L D' R B2 R' F2 D2 R2 F2 D2 B2 U2 L' F2 R U2 B2 L2
B L' U R F' U2 F2 L F2 L2 D2 L D' // 13 4b2 6e R B2 L' (L2 B2 U2 R' F2 R) (B2 D2 F2 U2 R2 F2 U2) // 29 slice, +0
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March 26, 2026 8:21 AM
Final
#6MeanDNFSingle23 (DNF / 23 / 25)
Attempt 1
Scramble
R' U' F D B' R U' D' F U2 R' D2 F2 L' F2 L' B2 R F2 L U F2 R' U' F
Results
DNF
My best DR, couldn't find a finish in time: U' F' D2 B' L2 B2 R U2 R F2 R' D // 12 4c3
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March 26, 2026 8:25 AM
Attempt 2
Scramble
R' U' F U' F2 D' R' B' U2 L2 D R2 U2 B2 L2 U2 R U L D' F2 R B' R' U' F
Results
23
R2 L2 B2 U' L2 U2 R2 L2 D' F2 D2 F' B2 D F' D2 B2 U F' U L' F B'
(F' B L) (U' F, U' B2 D2 F D' F) // 11 4b2 6e // I originally found the HTR finish using a 2e2e insertion: L2 R2 B2 U' R2 @ D F2 D2 B2 // 20 2e2e @ => R2 L2 U2 R2 L2 D2 // 6-3 = 23 finish // It is kinda explainable with this approach: L2 R2 B2 U' // switch after first qt (B2 D2 F2 D) // HTR extension that makes blocks (L2 R2 U2 L2) // finish
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March 26, 2026 8:45 AM
Attempt 3
Scramble
R' U' F R2 D2 B F D2 B L2 U2 L2 D2 R D F' D2 U L B2 F U' B R' U' F
Results
25
D2 R2 L2 U R2 U2 D B' R2 L2 F2 R2 L2 D R2 U L2 U' L2 U F2 B' L' F U
(U' F' L) (B) D2 R2 L2 U R2 D U2 B // 12 2c4 // I once again used a 2e2e insertion to find this: $ D R2 U L2 U' L2 U F2 // 20 2e2e $ => B2 L2 R2 F2 L2 R2 // 6-1 = 25 finish // This one is a lot easier to explain if I just did the HTR from the inverse (F2 U' L2 D^ F2 U' B2 U^') (L2 R2 F2 L2 R2 B2) // 25 4x ^ => w // +0 rewrite
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March 26, 2026 9:05 AM